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9y^2-43y+34=0
a = 9; b = -43; c = +34;
Δ = b2-4ac
Δ = -432-4·9·34
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-25}{2*9}=\frac{18}{18} =1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+25}{2*9}=\frac{68}{18} =3+7/9 $
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